STEM REASONING AND EVIDENCE WORKBENCH
Resolve launch velocity and calculate ideal horizontal and vertical checkpoint positions with a supplied gravity value.
Review output
Load the worked example to inspect realistic inputs, or enter anonymous classroom or laboratory evidence. Results remain in this browser tab until you copy or download them.
Transparent method
Horizontal velocity is v cos theta and vertical launch velocity is v sin theta. Horizontal position is v-x times elapsed time. Vertical position is launch height plus v-y times time minus one half g times time squared. The engine compares both coordinates with a small absolute or relative numeric tolerance. A supported checkpoint agrees with the ideal model for the entered values. A negative calculated y means the mathematical path has passed the landing reference and may be after physical impact. Compare predictions with measured coordinates and uncertainty, and explain separately why horizontal acceleration is zero while vertical acceleration is downward in the model.
Confirm the question, approved source, units, notation, signs, response coding, model assumptions, and review threshold. Keep an unchanged copy of measurements or learner evidence.
Run the worked example, inspect every intermediate row, and compare the result with a hand calculation, diagram, representation, periodic table, or approved laboratory method.
Record the method, assumptions, uncertainty, units, classifications, and flagged rows. Verify the editable report independently before instruction, assessment, or laboratory use.
How to interpret the result
Use for ideal two-dimensional projectile checkpoints after learners have declared axes and resolved launch velocity. It does not include air resistance, spin, wind, lift, changing gravity, moving reference frames, terrain, bounce, uncertainty, video calibration, or apparatus safety. It is unsuitable for planning real launches.
A horizontal 10 m/s launch from 5 m reaches x 5 and y 3.775 at 0.5 s. A 20 m/s launch at 30 degrees gives the reviewed one-second and two-second coordinates. The last 45-degree row has the right horizontal value but its vertical claim ignores enough gravitational drop and is flagged.
Horizontal velocity is v cos theta and vertical launch velocity is v sin theta. Horizontal position is v-x times elapsed time. Vertical position is launch height plus v-y times time minus one half g times time squared. The engine compares both coordinates with a small absolute or relative numeric tolerance.
A supported checkpoint agrees with the ideal model for the entered values. A negative calculated y means the mathematical path has passed the landing reference and may be after physical impact. Compare predictions with measured coordinates and uncertainty, and explain separately why horizontal acceleration is zero while vertical acceleration is downward in the model.
Do not use degrees as radians, apply gravity horizontally, drop the launch height, use total speed for both components, choose the wrong sign for gravity, or continue a real trajectory after impact. Draw axes, resolve the vector, check units and limiting cases, and keep real launch areas controlled and guarded.
Learning boundary
This browser-local workbench applies only the disclosed rules. It cannot diagnose a learner, certify an experiment, establish a chemical structure, or replace teacher, laboratory, and safety judgment.
Review checklist
Practical questions
No. Processing occurs in the current browser tab. Avoid personal information and retain authoritative records only in the school-approved system.
No. It describes entered evidence under one disclosed rule. Compare several evidence sources and ask for reasoning before drawing a conclusion.
Treat it as an editable calculation aid. Show your own reasoning, cite required sources, and follow the course method and academic-integrity rules.
YOUR NIRMION
