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STIRLING PERMUTATIONS / ASCENTS

Second Order Eulerian Number Calculator

Count Stirling permutations of order n having exactly k ascents under the stated second-order Eulerian convention.

  • 01 Calculated in this tab
  • 02 Values stay in this browser tab
  • 03 Use boundary

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METHOD / WORKED EXAMPLE

Audit the Second Order Eulerian Number result step by step

Count Stirling permutations of order n having exactly k ascents under the stated second-order Eulerian convention. The result panel keeps the defining recurrence or counting identity visible so the output can be checked independently.

WORKED DEFAULT

Check the calculation with the default inputs

At order n = 5 and ascent index k = 2, the second-order Eulerian recurrence gives 328.

  1. Set rown=5
  2. Apply recurrencetwo predecessors
  3. Read indexA(5,2)=328

READ THE RESULT

Interpret the output in context

This ascent distribution belongs to Stirling permutations and differs from first-order Eulerian numbers.

ASSUMPTIONS AND LIMITS

Know where the model stops

  • The supplied order and ascent index are nonnegative integers.
  • For positive n, k ranges from zero through n-1.

Indexing conventions vary in references; this page states and tests its zero-based k convention.

COMMON QUESTIONS

Second Order Eulerian Number Calculator FAQs

What definition does Second Order Eulerian Number Calculator use?

Start from the one-entry base row and build each bounded row with the second-order Eulerian two-predecessor recurrence. The indexing, equivalence relation, and counted objects are stated in the method and worked example. Inputs must be whole numbers inside the displayed domain; the page never rounds a decimal into an accepted index. This ties the answer to one explicit convention instead of silently mixing sequence offsets or combinatorial interpretations.

How can I verify the Second Order Eulerian Number output?

This ascent distribution belongs to Stirling permutations and differs from first-order Eulerian numbers. Small boundary cases and the displayed recurrence or identity provide useful independent checks. Recompute the displayed recurrence or closed form with the same inputs and compare its previous terms or counting factors. That check supports this bounded result, but it does not transfer the interpretation to a different sequence or counting object.

Why is the Second Order Eulerian Number input bounded?

Indexing conventions vary in references; this page states and tests its zero-based k convention. The implementation uses integer arithmetic internally and refuses results beyond the safe display boundary. Combinatorial and recurrence values can grow rapidly even when the inputs look small. The conservative cap prevents browser stalls and avoids presenting an unsafe floating-point integer as exact; larger work needs arbitrary-precision software and independent resource controls.

Use boundary

Calculation path

Start from the one-entry base row and build each bounded row with the second-order Eulerian two-predecessor recurrence.

Calculation path

A(n,k)=(k+1)A(n-1,k)+(2n-k-1)A(n-1,k-1).