Nirmion
ヘルプ ツールを探す

LATTICE PATHS / DIAGONAL BOUNDARY

Large Schroder Number Calculator

Count large Schroder paths of semilength n that stay weakly below the diagonal with horizontal, vertical, and diagonal steps.

  • 01 Calculated in this tab
  • 02 Values stay in this browser tab
  • 03 Use boundary

Conversion input

Known value

Filter by unit name, symbol, or code. Your current selections remain available.

Preparing the calculator...

METHOD / WORKED EXAMPLE

Audit the Large Schroder Number result step by step

Count large Schroder paths of semilength n that stay weakly below the diagonal with horizontal, vertical, and diagonal steps. The result panel keeps the defining recurrence or counting identity visible so the output can be checked independently.

WORKED DEFAULT

Check the calculation with the default inputs

At n = 5, the large Schroder recurrence gives 394 paths.

  1. Set semilengthn = 5
  2. Convolve earlier termsS0 through S4
  3. Return exact countS5 = 394

READ THE RESULT

Interpret the output in context

This is the large Schroder convention; the little sequence counts a different boundary treatment.

ASSUMPTIONS AND LIMITS

Know where the model stops

  • The path starts and ends on the square diagonal.
  • Horizontal, vertical, and double diagonal steps follow the stated Schroder model.

n is capped at 23 to keep the exact recurrence responsive and safely displayable.

COMMON QUESTIONS

Large Schroder Number Calculator FAQs

What definition does Large Schroder Number Calculator use?

Start with S(0)=1 and apply S(n)=S(n-1)+the convolution of all earlier complementary index pairs. The indexing and counted objects are stated in the method and worked example. Inputs must be whole numbers inside the displayed domain; the page never rounds a decimal into an accepted index. This ties the answer to one explicit convention instead of silently mixing sequence offsets or combinatorial interpretations.

How can I verify the Large Schroder Number output?

This is the large Schroder convention; the little sequence counts a different boundary treatment. Small boundary cases and the displayed identity provide useful independent checks. Recompute the displayed recurrence or closed form with the same inputs and compare its previous terms or counting factors. That check supports this bounded result, but it does not transfer the interpretation to a different sequence or counting object.

Why is the Large Schroder Number input bounded?

n is capped at 23 to keep the exact recurrence responsive and safely displayable. The implementation uses integer arithmetic internally and refuses results beyond the safe display boundary. Combinatorial and recurrence values can grow rapidly even when the inputs look small. The conservative cap prevents browser stalls and avoids presenting an unsafe floating-point integer as exact; larger work needs arbitrary-precision software and independent resource controls.

Use boundary

Calculation path

Start with S(0)=1 and apply S(n)=S(n-1)+the convolution of all earlier complementary index pairs.

Calculation path

S(n)=S(n-1)+sum S(k)S(n-1-k).