STEM PRACTICE AND EVIDENCE WORKBENCH
Calculate inverse-square gravitational field strength from source mass and center-to-center radius and audit learner values.
Review output
Load the worked example to inspect realistic inputs, or enter anonymous classroom or laboratory evidence. Results remain in this browser tab until you copy or download them.
Transparent method
Field magnitude g equals G times source mass M divided by center-to-center radius r squared. Doubling mass doubles field at fixed radius; doubling radius reduces field to one quarter. The table exposes G times M and r squared before division, and the learner comparison uses the entered percentage tolerance. Supported means the scalar magnitude matches the bounded inverse-square model. A mismatch may reflect a missing square, surface radius versus altitude confusion, incompatible G units, an exponent error, or early rounding. Agreement does not confirm direction, spherical symmetry, significant figures, or suitability of the physical model.
Confirm the question, source, units, notation, response coding, model assumptions, and review threshold. Keep an unchanged copy of the original evidence.
Run the worked example, inspect every intermediate row, and compare it with a hand calculation, diagram, representation, or approved subject method.
Record the method, assumptions, units, classifications, and flagged rows. Verify the editable report independently before educational or laboratory use.
How to interpret the result
Use for point-mass or spherically symmetric field models when learners need to trace mass scaling and the inverse-square radius effect. It does not calculate a field inside an extended body, add fields from several sources, preserve vector direction, validate a planet model, choose units automatically, or replace a full derivation.
Using the supplied SI gravitational constant, the Earth-like and Moon-like rows produce familiar surface field magnitudes near 9.82 and 1.62. A one-trillion-kilogram source at ten metres gives about 0.667. The review row places ten billion kilograms at two metres, where inverse-square division gives about 0.167 rather than 0.20.
Field magnitude g equals G times source mass M divided by center-to-center radius r squared. Doubling mass doubles field at fixed radius; doubling radius reduces field to one quarter. The table exposes G times M and r squared before division, and the learner comparison uses the entered percentage tolerance.
Supported means the scalar magnitude matches the bounded inverse-square model. A mismatch may reflect a missing square, surface radius versus altitude confusion, incompatible G units, an exponent error, or early rounding. Agreement does not confirm direction, spherical symmetry, significant figures, or suitability of the physical model.
Do not use diameter as radius, measure from a surface instead of the source center, multiply by radius squared, omit scientific-notation exponents, confuse field with total force, mix kilometres and metres, or infer vector direction from a scalar. Draw the geometry, state units, and test scaling before accepting a result.
Learning boundary
This browser-local workbench applies only the disclosed rules. It cannot diagnose a learner, certify an experiment, or replace teacher, laboratory, and safety judgment.
Review checklist
Practical questions
No. Processing occurs in the current browser tab. Avoid personal information and retain authoritative records only in the approved school system.
No. It describes entered evidence under one disclosed rule. Review reasoning, uncertainty, access, and several evidence sources.
Treat it as an editable calculation aid. Show your own reasoning, cite required sources, and follow course and academic-integrity rules.
YOUR NIRMION
