STEM REASONING AND EVIDENCE WORKBENCH
Calculate signed interval displacement and average velocity, then audit learner slopes from position-time endpoints.
Review output
Load the worked example to inspect realistic inputs, or enter anonymous classroom or laboratory evidence. Results remain in this browser tab until you copy or download them.
Transparent method
Duration equals ending time minus starting time and must be positive. Signed displacement equals ending position minus starting position. Average velocity equals displacement divided by duration, which is the secant slope between the two points. Positive, zero, and negative results follow the declared coordinate direction. A supported claim matches the interval slope within one percent. It does not establish uniform motion inside the interval because faster and slower segments can share the same average. Inspect the full graph or time-series evidence, coordinate signs, sampling interval, resolution, uncertainty, and context before describing motion.
Confirm the question, approved source, units, notation, signs, response coding, model assumptions, and review threshold. Keep an unchanged copy of measurements or learner evidence.
Run the worked example, inspect every intermediate row, and compare the result with a hand calculation, diagram, representation, periodic table, or approved laboratory method.
Record the method, assumptions, uncertainty, units, classifications, and flagged rows. Verify the editable report independently before instruction, assessment, or laboratory use.
How to interpret the result
Use for discrete position-time intervals when learners need to interpret slope as signed average velocity. It supports forward, rest, and reverse intervals. It does not reconstruct a continuous graph, calculate instantaneous velocity, determine distance traveled between endpoints, correct sensor timing, propagate uncertainty, or prove constant velocity.
The first interval moves six metres in two seconds for positive three metres per second. A horizontal interval has zero displacement and velocity. The next interval returns four metres in two seconds for negative two. The last interval rises six metres in two seconds, so a learner claim of two instead of three is flagged.
Duration equals ending time minus starting time and must be positive. Signed displacement equals ending position minus starting position. Average velocity equals displacement divided by duration, which is the secant slope between the two points. Positive, zero, and negative results follow the declared coordinate direction.
A supported claim matches the interval slope within one percent. It does not establish uniform motion inside the interval because faster and slower segments can share the same average. Inspect the full graph or time-series evidence, coordinate signs, sampling interval, resolution, uncertainty, and context before describing motion.
Do not divide position by time without subtracting endpoints, use absolute distance in place of displacement, reverse the time order, call a negative slope negative speed, or assume average equals instantaneous velocity. Draw the two points, show rise over run with units, and describe the chosen positive direction.
Learning boundary
This browser-local workbench applies only the disclosed rules. It cannot diagnose a learner, certify an experiment, establish a chemical structure, or replace teacher, laboratory, and safety judgment.
Review checklist
Practical questions
No. Processing occurs in the current browser tab. Avoid personal information and retain authoritative records only in the school-approved system.
No. It describes entered evidence under one disclosed rule. Compare several evidence sources and ask for reasoning before drawing a conclusion.
Treat it as an editable calculation aid. Show your own reasoning, cite required sources, and follow the course method and academic-integrity rules.
YOUR NIRMION
